Can someone please explain how the UV sensor output values (current) should be converted to an illumination intensity? From the wiki page it looks like a simple application of V=IR to get a voltage from the current output. Then the next step is to obtain illumination intensity by multiplying by 307 (mW/m2). However, I do not see why 4980.0 was used as the resistance or why 307 is the appropriate factor...
Thanks in advance for your time!
Statistics : Posted by daniel.haaland • on Wed Apr 08, 2015 3:23 am • Replies 1 • Views 21
Thanks in advance for your time!
Statistics : Posted by daniel.haaland • on Wed Apr 08, 2015 3:23 am • Replies 1 • Views 21